### Author Topic: 智力斗大  (Read 22588 times)

#### gentoo

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##### 智力斗大
« on: 三月 31, 2008, 01:39:59 am »
18张 对 4张  2最大 3最小；

« Last Edit: 七月 02, 2013, 04:42:48 pm by 万精油 »

#### 万精油

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##### Re: 智力斗大
« Reply #1 on: 三月 31, 2008, 08:11:21 am »

#### idiot94

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##### Re: 智力斗大
« Reply #2 on: 三月 31, 2008, 11:07:23 am »

In general, the men of lower intelligence won out. Afraid of of their own shortcomings ... they boldly moved into action. Their enemies, ...  thought there was no need to take by action what they could win by their brains. Thucydides, History

#### 万精油

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##### Re: 智力斗大
« Reply #3 on: 三月 31, 2008, 08:45:36 pm »

#### gentoo

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##### Re: 智力斗大
« Reply #4 on: 三月 31, 2008, 09:54:17 pm »

1) 多牌方出2后也不敢再出单牌

2) 若不出，少牌方继续出JJ后，多牌方必须出KK或QQ，结果将剩下4和K或Q其中一张共两张比A小的单牌

#### 万精油

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##### Re: 智力斗大
« Reply #5 on: 四月 01, 2008, 12:04:49 am »
ID94说正解很长的时候我就已经发现一张一张出牌的错误了。不过，我觉得发现错误本身就是一到很有意思的题目，所以就贴了请人指出错误的贴子。现在GENTOO已经指出错误，该考虑正解了。

#### packman

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##### Re: 智力斗大
« Reply #6 on: 四月 01, 2008, 07:24:37 am »
Not sure if it is correct.

Single K first. Then single 3. Then one by one from the smallest.

Even after the pair of Ace is broken, you can let it go again.
« Last Edit: 四月 01, 2008, 07:47:07 am by packman »

#### 万精油

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##### Re: 智力斗大
« Reply #7 on: 四月 01, 2008, 10:04:43 am »
Quote
Single K first. Then single 3. Then one by one from the smallest.

Even after the pair of Ace is broken, you can let it go again.

If you play single K first. He let you go. When you play single 3, he let you go. When you play single 4, he will play J, you have to cover it with Q. Then, your pair K and Q cannot split any more when he covers your singleton with J next time.

#### 万精油

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##### Re: 智力斗大
« Reply #8 on: 四月 01, 2008, 02:11:35 pm »
I haven't thought it through carefully yet, but it seems to me if you catergorize the cards into straight 34567 and flush (all dimonds), you are left with a single 6 and some pairs. Thus, the first card should be 6. The rest of them should follow (very complicated).

#### idiot94

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##### Re: 智力斗大
« Reply #9 on: 四月 01, 2008, 06:55:06 pm »
I haven't thought it through carefully yet, but it seems to me if you catergorize the cards into straight 34567 and flush (all dimonds), you are left with a single 6 and some pairs. Thus, the first card should be 6. The rest of them should follow (very complicated).
I do not remember (well, never really knew actually) the solution, but this sounds like the right approach. (I remember seeing that flush..)
In general, the men of lower intelligence won out. Afraid of of their own shortcomings ... they boldly moved into action. Their enemies, ...  thought there was no need to take by action what they could win by their brains. Thucydides, History

#### packman

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##### Re: 智力斗大
« Reply #10 on: 四月 02, 2008, 09:04:07 am »
Damn this problem. I even worked on it in my dream last night.

#### 万精油

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##### Re: 智力斗大
« Reply #11 on: 七月 02, 2013, 04:39:50 pm »

----ZTZTZT----------------------------------------------------------

1。第一张出6，剩下的牌分为：34567，457QK，99，QQ，KK, 2

a，出J，压Q：出A，压2胜出；不出A，继续出Q，出K，另一个K。胜出
b，出A，压2：胜出

2。第二张再出6，剩下的牌分为：3，44，55 77，99，QQQ，KKK, 2（方案一）或234QK，4，55，77，99，QQ，KK（方案二）

a，出J，采用方案一牌型，压Q：出A，压2。胜出。不出A，出3，出4，。。。一直出单张。如果对方出J，用K压。胜出
b，出A，采用方案二牌型，PASS。出对J，压对QQ，胜出。出A或J，采用方案一牌型，压2胜出。

3。第三张出3，剩下的牌分为：44，55 77，99，QQQ，KKK, 2

a，出J，采用2，a的方法。胜出
b，出A，压2胜出。

4。第四张出9，剩下的牌分为：9，44，55 77，QQQ，KKK, 2（方案一）或249QK，4，55，77，QQ，KK（方案二）
a，出J，采用方案一牌型，压Q：出A，压2。胜出。不出A，出9，出4，。。。一直出单张。如果对方出J，用K压。胜出
b，出A，采用方案二牌型，PASS。出对J，压对QQ，胜出。出A或J，采用方案一牌型，压2胜出。

5。第五张出9，剩下的牌分为：44，55 77，QQQ，KKK, 无论对方出什么。压2。两个3带2。胜出
« Last Edit: 七月 03, 2013, 01:55:46 pm by 万精油 »

#### packman

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##### Re: 智力斗大
« Reply #12 on: 七月 02, 2013, 06:32:59 pm »